
c * t1 = A0B0 , A0B0 = 100: t1 = 100: B0  B1 = 100 = A0  A1 A0C0 = A0B0 + v * t2 = c * t2 : t2 = A0B0/(cv) : t2 = 125 : C2  C0 = 125 v * t3 + c* t3 = 2 * A0C0 : t3 = 2 * A0C0 / (v + c) : t3 = 208,33 D0  D3 = 208,33 A0  A1 = 100 , A0  A2 = 125, A0  A3 = 200, A0  A4 = 250 
Consider one sets of identical clocks, all clocks moving with the same speed, all clocks are at a fixed distance of each other, all clocks are synchronized and show the same time. This is set 1 and each clock is called clock 1.
Consider a second set of identical clocks. This is set 2 and each clock is called clock 2.
The difference beteen set 1 and set 2 that the clocks of set 2 have a speed v relative to set 1.
When you consider both sets as a total than the whole group is not synchronised implying that not all clocks can show universal time.



Figure 1A is based on the concept that the clocks of C1 and C2 are initialized when they meet with a count of 100 and that all the clocks are synchronised with this same count using Einstein synchronisation.
In Figure 1A the difference between C1 and C2 = 0. In Figure 1B the difference between D1 and D2 = 20 and in Figure 1 C the difference is 40. That means there is a linear increase.






This seems simple but is it correct? The problem starts when you consider clocks in a moving frame.
  / Q  / . . /  / . x  / . . /  x . /  / . . / / S /  
In the picture at the left we have one source which transmits two light signals. They will both reach the point Q (Clock 2) simultaneous. When we issue a synchronisation signal of 1005, this signal will not reach the two points x simultaneous in the frame at rest. 

Figure 3 shows the different arriving times in arbitrary direction. Clock 1 is at the origin O and clock 2 is at the position marked 2. In all the cases the signal is transmitted when T1 of clock 1 is 2000 and T2 of clock 1 is 2010. 

Figure 4 shows the source at O and 4 four detectors marked N,E,S, and W The idea behind is to study this process from two perspectives.

1 2 3 4 5 6 7 8 9 t0 1' 2' 3' 4' 5' 6' 7' 8' 9' > t1 1' 2' 3' 4' 5' 6' 7' 8' 9' > Figure 5 
1 2 3 4 5 6 7 8 9 t1 1' 2' 3' 4' 5' 6' 7' 8' 9' > t2 1' 2' 3' 4' 5' 6' 7' 8' 9' > t7 1' 2' 3' 4' 5' 6' 7' 8' 9' > t14 1' 2' 3' 4' 5' 6' 7' 8' 9' > Figure 6 

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